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3 years ago

7 + z < 3 Can someone help me solve this inequality please?

2 answers:

8 0

The answer is z < -4

To find the answer to an inequality, you treat it just like an equation and try to get the variable by itself. So, to do this we subtract 7 from both sides and we get z < -4

Hope this helped!!! :)

Montano1993 [528]3 years ago

7 0

7 + z < 3

You solve this the same way you would any other algebraic expression such as..

7 + x = 3.

So, just subtract the seven from the three and you have your answer!

7 + z < 3

7 + z - 7 < 3 - 7

z < -4

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Drupady [299]

Answer:

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Step-by-step explanation:

2x =y

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3 years ago

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3 years ago

Read 2 more answers

Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

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