All categories

3 years ago

Here jwu4444 thank u so much

Mathematics

2 answers:

Galina-37 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

riadik2000 [5.3K]3 years ago

4 0

Answer:

you're welcome

glad to help!

You might be interested in

How much water does it take to completely fill a small pool that is 10 feet long, 20 feet wide and 10 feet deep?

irinina [24]

Answer:

2,000 feet cubed

Step-by-step explanation:

To find volume, you use the formula Length x Width x Height. When you plug in the numbers from this equation into that formula you get 10 x 20 x 10. 10 x 20 x 10 = 2,000.

8 0

4 years ago

Read 2 more answers

Pedro opened a grilled cheese food cart. He insures his food cart for $90,000.00 for fire. What's his premium if the rate per $1

Nonamiya [84]

1.) Divide the value of the grilled cheese food cart by $100
$90,000 / $100 = $900
2.) Multiply the quotient by the rate per $100
$900 * $.83 = $747
3.) Therefore, B. $747 is Pedro's premium for his grilled cheese food cart

3 0

3 years ago

Read 2 more answers

The ratio 20 minutes to 1hour can be written is n the form 1:n find the value of n

VARVARA [1.3K]

Answer:

Step-by-step explanation:

7 0

4 years ago

Can you guys help me with this

ivolga24 [154]

I think the answer is D

8 0

3 years ago

Question 9

Alenkasestr [34]

Answer:

$PX=4\\PY=4\sqrt{3}$

Step-by-step explanation:

Let $\angle PYZ=Q$

$\Rightarrow \angle XYP=90-\angle PYZ\\\angle XYP=90-\theta$

In the $\Delta PYZ$

$\tan\theta =\frac{opposite}{adjacent}=\frac{PZ}{PY}......(1)$

In the $\Delta YPX$

$\tan(90-\theta)=\frac{opposite}{adjacent}=\frac{PX}{PY}$

$\cot=\frac{PX}{PY}....(2)$

eqn(1) $\times$ eqn(2)

$\tan\times\cot\theta=\frac{PZ}{PY}\times\frac{PX}{PY}\\\\1=\frac{PZ\times PX}{PY^2}\ \ (as\ tan\theta\ =\frac{1}{\cot\theta})\\\\PY^2=PZ\times PX\\PY^2=12PX.......(3)$

Now in $\Delta XYP$

use Pythagorean theorem

$XY^2=PY^2+PX^2\\8^2=PY^2+PX^2\ \ (as\ XY\ =8)\\PX^2+PY^2=64\\\\PY^2=12PX\ \ (eqn(3)\\\\\Rightarrow PX^2+12PX=64\\\\PX^2+12PX-64=0\\\\PX^2+16-4PX-64=0\\\\(PX+16)(PX-4)=0\\\\PX=4,\ -16$

Length can not be negative

Hence $PX=4$

$PY^2=12PX=12\times4=48\\\\PY=\sqrt{48}=4\sqrt{3}$

Hence $PX=4,\ PY=4\sqrt{3}$

8 0

3 years ago