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3 years ago

PLEASE HELP ME OUT FAST MULTIPLE CHOICE IF YOU DOMT KNOW PLEASE DONT RIGHT ANYTHING!

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

7 0

Answer:

Step-by-step explanation:

When you are finding the solution of two lines on a graph, you look at the intersection point and that is the answer. On the given graph, both lines intersect at (4, -3). Thus, that is the solution.

Best of Luck!

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a formula for finding the perimeter of a rectangle is p=2L+2W if you know the perimeter (p) and width (w) of a rectangle which f

lbvjy [14]

Step-by-step explanation:

You can first multiply the width by two. Then you subtract that from you perimeter to figure out your length. Whatever number you get divide it by two and there's your length.

Example:

Perimeter =30 Width=5

5 times 2= 10

30-10=20

20/2=10

So your length equals 10.

I hope this helps!

4 0

3 years ago

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Joe will flip a coin 48 times. How many times can he expect to land on heads?

Semmy [17]

It could be 20 times or 25 times

3 0

3 years ago

17.25 round up to ones

Irina18 [472]

17.24

Since 7 comes after 5 we need to round to the next number.....18.00

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Hope I helped:P

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3 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$