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nikdorinn [45]
3 years ago
6

* WILL GIVE BRIANLIEST*(08.03)Consider the following set of equations:

Mathematics
2 answers:
cluponka [151]3 years ago
7 0
The third choice is very useful. It's​ valid because two things that are both equal to 'y' are equal to each other, and it can be easily solved to find 'x'.
stepan [7]3 years ago
5 0

Answer:

3rd choices

Step-by-step explanation:

U can use it To find the solution the others won’t work

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What is the area of the polygon shown
kvv77 [185]

Answer:

16 square units

Step-by-step explanation:

(bxh)÷2

4×8=32

32÷2=16

5 0
2 years ago
Question 22 please????
777dan777 [17]
[n] + [n+2] + [n+4] = -198

3n +6 = -198

3n = -198 -6 = -204
n = -204/3 = -68

1st even integer = -68

2nd even integer= n+2 = -68 + 2= -66

3rd even integer= n+4 = -68 + 4 = -64
5 0
3 years ago
What is the solution of 4x+9=2x-6?
Evgen [1.6K]

4x+9=2x−6

Step 1: Subtract 2x from both sides.

4x+9−2x=2x−6−2x

2x+9=−6

Step 2: Subtract 9 from both sides.

2x+9−9=−6−9

2x=−15

Step 3: Divide both sides by 2.

2x

2

=

−15

2

x=

−15

2

Answer:

x=-15/2




8 0
3 years ago
Which of the following equations is of a parabola with a vertex at (1, -1)?
Helen [10]
\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
(1,-1)\implies \begin{cases}
h=1\\
k=-1
\end{cases}\implies y=a(x-1)^2-1
\\\\\\
\textit{and if we assume \boxed{a=1} then}\implies y=(x-1)^2-1
5 0
3 years ago
I have no clue Hawke to do this
Oksanka [162]
7. y-axis
8. x-axis
9. x-axis
10. y-axis

Hope this helped! :) 

(pls give me brainliest answer if you can, I'm desperate)
6 0
3 years ago
Read 2 more answers
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