Answer:
0.5<2-√2<0.6
Step-by-step explanation:
The original inequality states that 1.4<√2<1.5
For the second inequality, you can think of 2-√2 as 2+(-√2).
Because of the "properties of inequalities", we know that when a positive inequality is being turned into a negative, the numbers need to swap and become negative. So, the original inequality becomes -1.5<-√2<-1.4. (Notice how the √2 becomes negative, too). This makes sense because -1.5 is less than -1.4.
Using our new inequality, we can solve the problem. Instead of 2+(-√2), we are going to switch "-√2" with both possibilities of -1.5 and -1.6. For -1.5, we would get 2+(-1.5), or 0.5. For -1.4, we would get 2+(-1.4), or 0.6.
Now, we insert the new numbers into the equation _<2-√2<_. The 0.5 would take the original equation's "1.4" place, and 0.6 would take 1.5's. In the end, you'd get 0.5<2-√2<0.6. All possible values of 2-√2 would be between 0.5 and 0.6.
Hope this helped!
The measure of ∠C is 54°.
<h3>To solve the problem :</h3>
let us assume that line n is a mirror.
∴ ∠A = ∠A' = 59°
∠B = ∠B' = 67°
∠C = ∠C'
According to property of triangles :
Sum of all angles of a triangle is 180°.
∴ A + B + C = 180°
59 + 67 + C = 180
C = 
C = 54°
<h3>∴ The measure of ∠C is 54°.</h3>
To know more about triangles refer to :
brainly.com/question/1620555
#SPJ2
Answer:
so I'm not 100% sure but in these types of questions you are supposed to divide
so you have a pack of 24 bottles for 7.99
so you would do 7.99÷24 = 0.33
then to check it you can multiply
0.33× 24 bottles and it gives you 7.93 which is super close to 7.99 anyway I hope this helps ...
Answer:
Step-by-step explanation:
The parent log function has a vertical asymptote at x=0, so the asymptote at x=-3 indicates a left shift of 3 units.
The parent log function crosses the x-axis 1 unit to the right of the vertical asymptote, which this one does, indicating there is no vertical shift.
The parent log function has an x-value equal to its base when it has a y-value of 1. Here, the y-value of 1 corresponds to an x-value 3 units to the right of the vertical asymptote, so the base of this logarithm is 3.
The function is ...
