I think the answer is D. I’m bot sure though I learned about this last year so my memory on it isn’t the best
Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
Answer:
The correct answer is C. benefit ... harmed
Explanation:
Predation is a type of interaction between two individuals in which one individual gets harmed which is called prey and another organism who is predator gets benefitted.
In predation, the predator kills its prey and consume it to survive. For example, Lion is a predator and deer is the prey so during predation lion kills the deer and consume it so here lions get benefited by consuming deer and deer is harmed as it lost its life. So the correct answer is C. benefit ... harmed.
Answer: Food storage
Explanation:
Stomach is a small pouch like structure which has the ability to store food temporarily.The storage of the food temporarily takes place in the stomach. The food that we eat reaches to the stomach by the help of food pipe.
Here, the food is stored until it is completely broken down into simpler form and enzymes act on them.
The food is then absorbed in the small intestine. But before this food is temporarily stored in the stomach where all the digestive juices and enzymes come to act on the food.
