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Elenna [48]
3 years ago
9

2. If a marble is selected at random from Adrian's Bag of Marbles,

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

9 out of 16

Step-by-step explanation:

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lina2011 [118]

Answer:

Step-by-step explanation:

8 0
3 years ago
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Step by step on how to solve this equation 2 x + 3 = x − 4 because I fogot how to do basic math
valentina_108 [34]

Answer:

-7

Step-by-step explanation:

2x +3 =x-4

2x - x =-4 - 7

x=-7

4 0
3 years ago
What two numbers multiply to -36 and add up to -9
Softa [21]

Answer:

-12,3

Step-by-step explanation:

-12×3=-36

-12+3=-9

3 0
2 years ago
Mr. Sims wants to buy a new truck. He sold his old truck for $3,582, and he has $4,979 in the bank. If a new truck costs $9,005,
Colt1911 [192]

Answer:

$444

Step-by-step explanation:

3,582 + 4,979 = 8,561

9,005 - 8,561 = 444

7 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day. Legacy
inessss [21]

Answer:

We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

<u><em>Let </em></u>\mu<u><em> = average water usage by residents of Legacy Ranch.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 67 gallons     {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, H_A : \mu < 67 gallons    {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                                 T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean water use per day = 63 gallons

             s = sample standard deviation = 8.1 gallons

             n = sample of responded = 23

So, <u><em>test statistics</em></u>  =  \frac{63-67}{\frac{8.1}{\sqrt{23} } }  ~ t_2_2

                               =  -2.368

The value of the test statistics is -2.368.

<em>Now at 0.025 significance level, the </em><u><em>t table gives critical value of -2.074 at 22 degree of freedom for left-tailed test</em></u><em>. Since our test statistics is less than the critical values of t as -2.368 < -2.074, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to </em><u><em>which we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the residents of Legacy Ranch use less water on average.

8 0
3 years ago
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