The best thing is to have a ruler with the appropriate units to construct these triangles;)
Answer:
Step-by-step explanation:
Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
<span>regular pentagon sum of interior = (5 - 2) x 180 = 3 x 180 = 540
so
x = 540 / 5 = 108
180 - 108 = 72
y = 72/2 = 36
z = 180 - 90 - 36
z = 54
answer
x = 108, y = 36 and z = 54</span>
No because 0.6363.... <0.75
