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kotykmax [81]
4 years ago
7

Solve for the roots in the following equation. hint: factor both quadratic expressions. (x 4 5x 2 - 36)(2x 2 9x - 5) = 0

Mathematics
2 answers:
OleMash [197]4 years ago
7 0
Hello :
 <span>(x 4 +5x²  - 36)(2x ²+ 9x - 5) = 0</span>

Hoochie [10]4 years ago
4 0

The roots are 2,-2,3i,-3i,1/2,-5

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Write Y=4/3x-4 in slope intercept form
sergij07 [2.7K]

Answer:

Y=4/3x-4

Step-by-step explanation:

You have it in slope intercept form =)

7 0
3 years ago
Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?
Lisa [10]

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

\bf \boxed{6a.1}~\hfill  \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill  \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\\\\\\\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

so let's do 6a1, 6a3 and 6a5.

\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \\\\\\ \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)\div (2\cdot 10)}\implies \stackrel{one}{90\div 20}~\hfill \stackrel{changing}{(9\cdot 70)\div(2\cdot 70)}\implies \stackrel{two}{630\div 140}

3 0
3 years ago
4.
Murrr4er [49]

Answer:

C. 2

Step-by-step explanation:

Use the formula  

x  =  − b /2 a

to find the maximum and minimum.

( − 3 , 2 )

4 0
3 years ago
If 6/10 = 21/K what is K​
timama [110]

You can cross multiply for this problem. So:

\frac{6}{10}=\frac{21}{K}\\6K=210\\K=35

So K=35!

Hope this helps! :)

3 0
3 years ago
A parallelogram has a base of 16 centimeters and a height of 4 centimeters
jasenka [17]

Answer:

Area = 64 cm²

Step-by-step explanation:

The area of a parallelogram is found by using the formula A = b x h

Where A is the area, b is the base and h is the height

A = 16 x 4

A = 64

4 0
3 years ago
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