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nika2105 [10]
3 years ago
6

If you can help me out with just one that'd be great!

Mathematics
1 answer:
ss7ja [257]3 years ago
8 0

4(0)2 .65

I got it right on there

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6+x6+x<br> 6+x<br> 6, plus, x<br> when <br> x=3x=3<br> x=3<br> x, equals, 3<br> .
fgiga [73]

Answer:

2196

Step-by-step explanation:

Okay so we have 6+x^{6} +x^{6} +x^{6} +x when x=3 since we know that x=3 we can rewrite the problem as 6+3^{6}+3^{6}+3^{6}+3 then it can be rewritten as (6+3)+(3*3^{6}) which would then become (9)+(3*729) then (9)+(2187) which finally equals 2196.

6 0
4 years ago
I’ll mark brainliest help please.
andrezito [222]

Answer:

7inches

Step-by-step explanation:

1x7

3 0
3 years ago
Read 2 more answers
Find two ratios equivalent to the ratio in exercise 1<br><br> 8:5<br> 4:19<br> 6:23
Ne4ueva [31]
To find equivalent ratios just factor the same number to both numerator and denominator. I will make the ratios simple by multiplying 2/2 and 3/3 to the originals. To check, set as fraction and cross multiply and you should have the same number. I will show you how to check by doing it to the first ratio.

8:5 16:10 24:15

Check:
8/5 = 16/10
(8)(10)=(5)(16)
80=80

8/5=24/15
(8)(15)=(5)(24)
120=120

4:19 8:38 12:57

6:23 12:46 18:69
5 0
3 years ago
Four times the sum of a number and 15 is at least 120. Let x represent the number. Find all possible values for x.
lorasvet [3.4K]
Four times the sum of a number and 15 is at least 120
Let ‘x’ represent the number.
 "The sum of a number and 15"
This can be written mathematically as x + 15
 Given that 4 times this sum is at least 120,
This means that 4 times the sum is greater than or equal to 120
This can be written mathematically as 4(x + 15) >= 120
 Solving for x
 4(x + 15) >= 120
4x + 60 >= 120
4x >= 120 – 60
4x >= 60
x >= 60/4
x >= 15
 x is greater than or equal to 15 <span>
</span>
4 0
3 years ago
How do I solve this problem?
Lilit [14]

Answer:

The diagonal is 14sqrt(2) ft

Step-by-step explanation:

The area of a square is given by

A =s^2 where s is the side length

196 = s^2

Take the square root of each side

sqrt(196) =sqrt(s^2)

14 = s

The side length is 14 ft

Now we can use the Pythagorean theorem to find the length of the diagonal

a^2 + b^2 = c^2

The side lengths of the triangle are s = 14, and the diagonal is the hypotenuse

14^2 + 14^2 = c^2

196+196 = c^2

392 = c^2

Take the square root of each side

sqrt(392) = sqrt(c^2)

sqrt(196 *2) = c

We can separate  this into two pieces  sqrt(ab) = sqrt(a) sqrt(b)

sqrt(196)sqrt(2) =c

14sqrt(2) = c

The diagonal is 14sqrt(2) ft

8 0
3 years ago
Read 2 more answers
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