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dimulka [17.4K]
2 years ago
7

PLEASE HELP ME!!!! and stop just answering for points:/

Mathematics
2 answers:
REY [17]2 years ago
4 0
She can only make 2 trail mixes
svet-max [94.6K]2 years ago
4 0
2 trail mixes is the answer
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What is the area of the triangle?<br> 16<br> 10<br> "T<br> 8
Alexxandr [17]

Answer:

40 unit^2.

Step-by-step explanation:

Area = 1/2 * base * altitude

= 1/2 * 8 * 10

= 40 unit^2.

6 0
2 years ago
What is the common ratio for this geometric sequence?<br> 5,15,45,135...
LiRa [457]

Answer:

3

Step-by-step explanation:

To find the common ration, we take the 2nd term and divide it by the first term

15/5  = 3

Let check by taking the third term and dividing by the 2nd term

45/15 =3

The common ratio is 3

5 0
3 years ago
3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3​
ankoles [38]

Given:

The equation is:

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

To find:

The value of a.

Solution:

We have,

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

On simplification, we get

(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}

(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}

On comparing both sides, we get

6-12a=-18

-12a=-18-6

a=\dfrac{-24}{-12}

a=2

And,

8-3a=2

-3a=2-8

a=\dfrac{-6}{-3}

a=2

Therefore, the value of a is 2.

3 0
2 years ago
Figure 14-3
enot [183]
The answer is D. SIS idk how to do this
Ur welcome
5 0
3 years ago
Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0
1 year ago
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