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3 years ago

Please Help Me! I need to pass.

1 answer:

6 0

42 is the answer

Explanation:
50% of 80 is half of 80 which is 40

Then you would add 40 with 5% of 40

What you would do then is 5% times 40 then you would change the 5% into a decimal which is 0.05 and multiply it by 40 , which would get u 2

Then you would add the price with tax
40+2 = 42

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Which of the following statements about f(x) is true

kap26 [50]

Answer is C I hope it helps

5 0

4 years ago

Over the last three evenings, Mary received a total of 116 phone calls at the call center. The third evening, she received 3 tim

Tanya [424]

<h2>Answer:</h2>

First day - 25 calls

Second day - 16 calls

Third day - 75 calls

<h2>Step-by-step explanation:</h2>

You need to set variables and create system of equations first.

First evening= x

Second evening= y

Third evening = z

x+y+z=116

z=3x

y=x-9

Now you plug in the values into the equation x+y+z=116

x+(x-9)+(3x)=116

5x-9=116

5x=125

x=25

You plug in the value of x into the other equations.

x= 25

z= 3*(25)=75

y=(25-9)=16

Rearrange so it corresponds with days...

First day - 25 calls

Second day - 16 calls

Third day - 75 calls

5 0

3 years ago

Read 2 more answers

Expand:X(3x-1)<br>please quickly

andreyandreev [35.5K]

Answer:

$x(3x - 1) \\ = {3x}^{2} - x$

8 0

3 years ago

Read 2 more answers

3rd question of the day. It's 59th and the LASt question PLEASE help I'll give brainly thing

forsale [732]

Answer:

Step-by-step explanation:

Area of the specified region = Area of larger circle - Area of smaller circle

Larger circle:

r = 16 + 3 = 19 m

Area = πr²

=π * 19 * 19

= 361π m²

Smaller circle:

r = 16 m

Area = πr²

=π * 16 * 16

= 256π m²

Area of the specified region = 361π - 256π = 105π m²

6 0

4 years ago

Given the equation f(x)=2x^2-14x+10, find g(x), the image of f(x) after a ry=x (reflection over the line y=x). Express your answ

Illusion [34]

Given:

The function is:

$f(x)=2x^2-14x+10$

The function g(x), the image of f(x) after a $r_{y=x}$ (reflection over the line y=x).

To find:

The function g(x).

Solution:

We have,

$f(x)=2x^2-14x+10$

Substitute $f(x)=y$ in the given function.

$y=2x^2-14x+10$

The function g(x), the image of f(x) after a $r_{y=x}$ (reflection over the line y=x). So, interchange x and y.

$x=2y^2-14y+10$

Now, we need to find the value of y.

$x=2(y^2-7y+5)$

$\dfrac{x}{2}=y^2-7y+5$ [Divide both sides by 2]

$\dfrac{x}{2}-5=y^2-7y$ [Subtract 5 from both sides]

Add both sides half of square of coefficient of y, i.e. $(\dfrac{-7}{2})^2$ , to make it perfect square.

$\dfrac{x}{2}-5+(\dfrac{-7}{2})^2=y^2-7y+(\dfrac{-7}{2})^2$

$\dfrac{x}{2}-5+\dfrac{49}{4}=y^2-7y+(\dfrac{7}{2})^2$

$\dfrac{x}{2}-5+\dfrac{49}{4}=\left(y-\dfrac{7}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

$\dfrac{x}{2}+\dfrac{49-20}{4}=\left(y-\dfrac{7}{2}\right)^2$

Taking square root on both sides, we get

$\pm\sqrt{\dfrac{x}{2}+\dfrac{29}{4}}=y-\dfrac{7}{2}$

$\dfrac{7}{2}\pm\sqrt{\dfrac{2x+29}{4}}=y$

$\dfrac{7}{2}\pm\dfrac{\sqrt{2x+29}}{2}=y$

$\dfrac{7\pm \sqrt{2x+29}}{2}=y$

Substituting $y=g(x)$ , we get

$\dfrac{7\pm \sqrt{2x+29}}{2}=g(x)$

Therefore, the required function is $g(x)=\dfrac{7\pm \sqrt{2x+29}}{2}$ .

6 0

3 years ago