T(t) = temp at any given time t = time. To = initial temp of the heated object ... A cake removed from the oven has a temperature of 210°F It is left to room that has a temperature of 70°F. After 30 minutes, the temperature of in is 140°F a. Use Newton's Law of Cooling to find a model for the temperatur ... 20 = 1402 -0.02317.
Answer:
We'll use the traditional "slope" formula, evaluating

To find f(5), plug in x = 5 to f(x).
3(5)^3 + 2 = 377
Same thing for f(3)
3(3)^3 + 2 = 83
So

Answer:
-$12
Step-by-step explanation:
Working backwards from the $63, you need to add back what was withdrawn and subtract what was deposited.
63+75+9+41+85-285= -$12
Answer:
1, 3, and 4 would be correct answers
Step-by-step explanation:
1.) <u>-x - 2x - 3y - 2y + 1 + 1 = -3x -5y + 2</u>
2.) -3x + 2y + 3y + 2 = -3x + 5y + 2
3.) <u>-3x - y - y - y - y - y + 2 = -3x - 5y + 2</u>
4.) <u>-x - x - x - y - y - y - y - y + 1 + 1 = -3x - 5y + 2</u>
5.) x + x + x + y + y + y + y + y + 1 + 1 = 3x + 5y + 2
Hope this helps!