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Rudik [331]
2 years ago
6

HELP ME I DON'T GET IT!!!!!

Mathematics
1 answer:
frutty [35]2 years ago
7 0

Answer:

  • Kamille is wrong

Step-by-step explanation:

<u>Kamille is wrong, because:</u>

  • √58 is between √49 and √64

or

  • 7 < √58 < 8

She needs about 8 inches ribbon not 60 inches

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Translate this sentence into an equation. 62 is the sum of 12 and Chrissy's age. Use the variable c to represent Chrissy's age.
Greeley [361]
62= 12+c

Which your answer is 50 cause if you take 62 and subtract it to 12 it's 50. So 50 + 12 = 62
5 0
3 years ago
Type a digit that makes this statement true.<br><br> 81,583,74_ is divisible by 6.
grigory [225]

Answer:

81583746

Step-by-step explanation:

It will be divisible by 6 if it ends in 6; when you divide you get 13,597,291‬.

7 0
2 years ago
Read 2 more answers
Pick any number and add 5 to it. Find the sum of the new number and the original number. Add 5 to the sum. Divide the new sum by
Oksana_A [137]

Answer: The final number is 5

Step-by-step explanation:

Picked number: 10

STEP are all according to what you stated

10+5=15 (first sentence)

15+10=25 (second sentence)

25+5=30 (third sentence)

30÷2-10=5 (fourth sentence)

The final number is 5.

3 0
3 years ago
Is 63.90 greater than 63.990
djverab [1.8K]

Answer:

63.90 is greater than63.990

3 0
2 years ago
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According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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