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Pavlova-9 [17]
3 years ago
11

If RT is greater than BA, which statement is true? By the converse of the hinge theorem, mC = mS. By the hinge theorem,TS > A

C. By the converse of the hinge theorem, mS > mC. By the hinge theorem, BA = RT.

Mathematics
2 answers:
Yuliya22 [10]3 years ago
8 0
I found the corresponding image of this problem.

Hinge theorem states "If 2 triangles have 2 sets of congruent sides, the larger included angle will have a longer side"

Converse Hinge theorem states, "<span>If the two sides of one triangle are congruent to two sides of another triangle, and the third side of the first triangle is greater than the third side of the second triangle, then the included angle of the first triangle is larger than the included angle of the second triangle."</span>

<span>By the converse of the hinge theorem, mC = mS. FALSE. EITHER ANGLE IS LARGER THAN THE OTHER

By the hinge theorem,TS > AC.  FALSE. CONGRUENT SIDES BASED ON THE GIVEN IMAGE.

By the converse of the hinge theorem, mS > mC. TRUE. 

By the hinge theorem, BA = RT. FALSE. 3RD SIDE OF EITHER TRIANGLE WILL BE LONGER THAN THE OTHER.


</span>

ioda3 years ago
4 0

Answer:

C

Step-by-step explanation:

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Makovka662 [10]

Answer:

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Step-by-step explanation:

For this problem, imagine the standard form, which is:

f(x) = ax² + bx + c = y

Using the table, and adding that y at the end, we can plug in and write out the following equations. (<em>Writing it out is important</em>):

f(-1) = a(-1)² + b(-1) + c = 14

f(0) = a(0)² + b(0) + c = 7

f(1) = a(1)² + b(1) + c = 4

f(2) = a(2)² + b(2) + c = 5

Now if this doesn't look familiar, it's actually a <u>systems of equations</u> using the a, b, and c elements as your three variables! If you simplify the equations:

f(-1) = a - b + c = 14

f(0) = c = 7

f(1) = a + b + c = 4

f(2) = 4a + 2b + c = 5

Something unique just happened. We have already defined what ' c ' is!

<u><em>c = 7</em></u>

Setting that aside, if you remove the f(x) portion of the equations, you're left with:

a - b + c = 14

a + b + c = 4

4a + 2b + c = 5

Using the two upper equations, if we add them together (you can do that as it doesn't change the values of the variables) you get:

2a + 2c = 18

Note: the ' b ' variables cancelled out in the addition [ b +  (-b) ]

If you further simplify the equation:

a + c = 9

Awesome. Now we already know that <u>c = 7</u>, so if you plug that into the equation:

a + 7 = 9

Solve for a. So then a = 2

Now that we know the following:

a = 2

c = 7

We can then use the equation:

a + b + c = 4

And solve for b!

2 + b + 7 = 4

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Simplify.

b = -5

Now at this point, since you know what a, b and c are, you can write the equation!

f(x) = 2x² - 5x + 7

You can confirm your work by putting any of the x values in the table through!

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3 years ago
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sattari [20]

x=3

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7 0
3 years ago
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The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

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z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area  = 320 sq meters

Now, Area of a Rectangle  = Length x Width

⇒  320  = K x  5K

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But as K represents a length hence, K ≠ -8

So, the <u>width of the rectangle = 8 meters</u>

and the<u> length  of the rectangle = 8 x 5 = 40 meters</u>

Now, Perimeter = 2(length + width)

                            = 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.

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