What is the value of 0.1561 rounded to the nearest tent in a decimal and a fraction

Please HELP I will give Brainliest!

ankoles [38]

The answer is the first page, first graph

5 0

3 years ago

What ja the slope intercept form of (-6,-3) and (-9,-2)

Y_Kistochka [10]

In order to find the slope intercept form of the given coordinates above (-6,-3)(-9,-2) then you need to use the point slope formula :y-y1=m(x-x1) .now allyou have to due is to label each of the given coordinates x1,y1 and x2 ,y2.This will help with the differentiation of the given coordinates.Once you have done this apply the info within the formula ,and you will get an answer of :y= -1/3x - 5 ,and of course your slope is -1/3 and the y-intercept is -5 .

6 0

3 years ago

Are points O, X, and U coplanar?

melomori [17]

Answer:

Yes.

Step-by-step explanation:

Any three points are always coplanar.

5 0

3 years ago

Read 2 more answers

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago

Help me with this please!

ruslelena [56]

Area of the quarter sector
Area of the entire circle = pi * r^2
Area of the quarter circle = pi r^2 / 4
r = 9
Area of the quarter circle = pi 9^2 / 4
Area of the quarter circle = pi 81/4 = 20.25 pi

Area of the triangle
Area pf the triangle = 1/2 b*h
b = h = r
r = 9
Area of the triangle = 1/2 9 * 9
Area of teh triangle = 1/2 81
Area of the triangle = 40.5

Area of the shaded area
The shaded area = Area of the 1/4 circle - area of the triangle
The shaded area = (20.24 pi - 40.5)ft^2

A <<<<<< Answer.

6 0

3 years ago