Question

The length of a rectangle is five times it’s width if the area of the rectangle is 320m^2 find its perimeter

Answer 1

Answer:

Perimeter of the rectangle = 96 meters.

Step-by-step explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area  = 320 sq meters

Now, Area of a Rectangle  = Length x Width

⇒  320  = K x  5K

or,$5K^{2} = 320\\or, K^{2} = \frac{320}{5} = 64$

So, the vlue of K = 8 or, K = -8

But as K represents a length hence, K ≠ -8

So, the width of the rectangle = 8 meters

and the length  of the rectangle = 8 x 5 = 40 meters

Now, Perimeter = 2(length + width)

                            = 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.