(20,-3),(19,-20) what is the slope of this

Stacy Smith has a $50,000 loan with a 10% annual interest rate. She paid $250 for a credit report, $300 for attorneys, $250 for

NeTakaya

(250+300+250+5,268)÷50,000
=0.12136*100=12.1%

6 0

3 years ago

Read 2 more answers

The population of a town increases at a rate of 5% every year. The population of this town was 10,400 in 2017. What will the pop

galben [10]

Answer:

The population of the town in 2020 will approx. be 12,039.

Step-by-step explanation:

The initial population in the year 2017 = 10,400

Increase in population every yea r = 5%

Now, 5% of 10, 400 = $\frac{5}{100} \times 10, 400 = 520$

Hence, the population in the year 2018 = 10,400 + 520 = 10,920

Now, in the year 2019

5% of 10, 920 = $\frac{5}{100} \times 10, 920 = 546$

Hence, the population in the year 2019 = 10,920 + 546 = 11,466

Now, in the year 2020

5% of 11,466 = $\frac{5}{100} \times 11,466 = 573.3$

or, the population in the year 2020 = 11,466 + 573.3 = 12,039.3

The population of the town in 2020 will approx. be 12,039.

6 0

2 years ago

Giving brainliest! Please show the working out

tiny-mole [99]

Answer:

see explanation

Step-by-step explanation:

(a)

OC = OB ( both radii of the circle )

Thus Δ BOC is isosceles with congruent base angles.

∠ BOC = ∠ BCO = 50°

(b)

∠ ACB = 90° ( angle in a semicircle ), then

∠ ACO = 90° - 50° = 40°

OA = OC ( both radii of the circle )

Thus Δ ACO is isosceles with congruent base angles.

∠ BAC = ∠ ACO = 40°

7 0

2 years ago

Which is steeper, a slide that rises 3 feet for every 2 feet of run, or a sliding pole that rises 5 feet for every 3 feet of run

mezya [45]

Answer:

59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.

Step-by-step explanation:

Step 1

Express the angle of inclination as follows;

Tan∅=H/R

where;

∅=angle of inclination

H=vertical rise

R=distance of run

Step 2

Determine the angle inclination when;

H=3 feet

R=2 feet

replacing;

Tan∅=(3/2)=1.5

∅=Tan^(-1)(1.5)

∅=56.31°

Determine the angle inclination when;

H=5 feet

R=3 feet

replacing;

Tan∅=(5/3)=1.67

∅=Tan^(-1)(1.67)

∅=59.03°

59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.

6 0

2 years ago

cylindrical vase holds 8,038.4 cubic centimeters of water. The height of the vase is 40 centimeters. What is the length of the r

iragen [17]

The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.

Step-by-step explanation:

The given is,

Volume of cylindrical vase = 8038.4 cubic centimeters

Height of the cylindrical vase = 40 centimeters

Step:1

Formula for volume of cylindrical vase,

$Volume, V=\pi r^{2} h$ ......................(1)

Where, r - Radius of cylindrical vase

h - Height of cylindrical vase

From the given,

V = 8038.4 cubic centimeters

h = 40 centimeters

Equation (1) becomes,

8038.4 $= \pi r^{2} 40$

$=(3.14)(40)r^{2}$ (∵ $\pi$ = 3.14 )

$8038.4 = 125.6 r^{2}$

$r^{2} = \frac{8038.4}{125.6}$

$r =\sqrt{64}$

r = 8 centimeters

Result:

The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.

7 0

2 years ago