Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
Here we are given the information that an insurance agent receives 16% commission on every premium paid.
Now we are given that a premium of $497.69 is paid.
Let us say $x is the commission paid on the policy with a premium of $497.69.
Let us try to find the amount x here.
So we have to find 16% of 497.69 to get the commission amount x.
So finding 16% of 497.69.
x= 16% of 497.69 = 0.16*497.69 = 79.63
Answer: Commission of $79.63 is paid on a policy with a premium of $497.69.
Answer:
15 cos(33°) m
Step-by-step explanation
Presumably m stands for meters.
If RS were 1, x would be cos(33°)
Multiply sides of triangle by 15 m
When calculating cos(33°) first make sure cos(90°) comes out zero, not -0.448...
Answer:
SDFGHJKLJJS HI
Step-by-step explanation:
