Question

Solve each quadratic equation using the most efficient method. 3x2+21x=0

Answer 1

For this case we have the following quadratic equation:

$3x ^ 2 + 21x = 0$

Dividing by 3 to both sides of the equation we have:

$x ^ 2 + 7x = 0$

We take common factor "x" from the left side of the equation:

$x (x + 7) = 0$

Thus, the values of "x" that satisfy equality are:

$x_ {1} = 0\\x_ {2} = - 7$

Answer:

The solutions are:

$x_ {1} = 0\\x_ {2} = - 7$