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DiKsa [7]
3 years ago
13

What si the slope of y=-5x+4x

Mathematics
2 answers:
frosja888 [35]3 years ago
6 0

Answer:

Use the slope-intercept form y=mx+b to find the slope m. m=−1

Step-by-step explanation:

lets take the x's away from: -5x+4x

That will be -5+4

-5+4=-1

Because remember:

When adding positive numbers, count to the right.

When adding negative numbers, count to the left.

When subtracting positive numbers, count to the left.

When subtracting negative numbers, count to the right.

I hope this helps.       :)

Bas_tet [7]3 years ago
4 0

Answer:

m= 4

Step-by-step explanation:

Rewrite the slope-intercept form

y = 4x - 5

the using the slope-intercept form, the slope-intercept is 4

sorry if this doesn't help

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
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Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

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Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

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