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2 years ago

Alguien me lo puede contestar :(?es para hoy, les agradecería mucho

Mathematics

1 answer:

Free_Kalibri [48]2 years ago

8 0

Answer:

Step-by-step explanation:

NO SE

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Can someone pls help me out

Vika [28.1K]

A is the answer I think

3 0

3 years ago

Solve by elimination.

Ulleksa [173]

I got (X,Y) (11,10)

7 0

3 years ago

The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.

Olegator [25]

Answer:

Step-by-step explanation:

{k - some integer}

2k+1 - the first odd integer (the least)

5(2k+1) - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5 - the next odd consecutive integer (third)

2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

- 10k -10k

-2k + 16 = 8

-16 - 16

-2k = -8

÷(-2) ÷(-2)

k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15

Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1

4 0

3 years ago

AN ARTICLE STATED THAT “INTERNAL SURVEYS PAID FOR BY DIRECTORY ASSISTANCE PROVIDERS SHOW THAT EVEN THE MOST ACCURATE COMPANIES G

yan [13]

Using the binomial distribution, there is a 0.3474 = 34.74% probability of getting one wrong number.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, the values of the parameters are given by:

p = 0.15, n = 10.

The probability of getting one wrong number is P(X = 1), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

P(X = 1) = C(10,1) x (0.15)¹ x (0.85)^9 = 0.3474

0.3474 = 34.74% probability of getting one wrong number.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0

2 years ago

The average college lecture hall (auditorium) can seat 60 students with a standard deviation of 21. Assume that a total of 60 le

fiasKO [112]

Answer:

The standard deviation of the sample mean is $\sigma _ {\= x } = 2.711$

Step-by-step explanation:

From the question we are told that

The mean is $\= x = 60$

The standard deviation is $\sigma = 21$

The sample size is $n = 60$

Generally the standard deviation of the sample mean is mathematically represented as

$\sigma _ {\= x } = \frac{\sigma }{\sqrt{n} }$

substituting values

$\sigma _ {\= x } = \frac{ 21 }{\sqrt{60} }$

$\sigma _ {\= x } = 2.711$

4 0

3 years ago

Alguien me lo puede contestar :(?es para hoy, les agradecería mucho ​

Alguien me lo puede contestar :(?es para hoy, les agradecería mucho