Complete the square
first isolate x terms
y=(x^2-4x)-9
complete square inside (take 1/2 of square of b )
-4/2=-2, (-2)^2=4
add 4-4 inside
y=(x^2-4x+4-4)-9
complete the square
y=((x-2)^2-4)-9
y=(x-2)^2-4-9
y=(x-2)^2-13
Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
Answer:
<u>a = 13</u>
Step-by-step explanation:
We should know that: The sum of the interior angles of the triangle = 180°
Given the measure of the angles: (6a - 2) , (5a - 13) and (5a - 13)
So,
(6a - 2) + (5a - 13) + (5a - 13) = 180°
16 a - 28= 180 ⇒ Add 28 to both sides
16 a = 180 + 28 = 208 ⇒ Divide both sides by 16
a = 208/16 = 13
See the attachment for the answer and enjoy :)
add this statement at the end...... "<span>Also, if she retires at 67, then there are 67-25=42 years of investment, which gives A=$53212.28"</span>
Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)