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Anarel [89]
3 years ago
15

At an annual teacher’s conference everyone is served tea with their dinner. Let H be the event that a randomly selected particip

ant puts honey in their tea. Let S be the event that a randomly selected participant puts sugar in their tea. Suppose that afteryears of collecting data, the staff of this conference have estimated the following probabilities.P(H) = 0.14 P(S) = 0.65 P(H or S) = 0.73Estimate P(H and S) and interpret this value in the context of the problem.A.P(H and S) = 0.06, The probability that a randomly selected participant puts sugar and honey in their tea is 0.06.B.P(H and S) = 0.06, The probability that a randomly selected participant puts sugar or honey in their tea is 0.06.C.P(H and S) = 0.79, The probability that a randomly selected participant puts sugar and honey in their tea is 0.79.D.P(H and S) = 0.79, The probability that a randomly selected participant puts sugar or honey in their tea is 0.79
Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

im looking for the same one :(

Step-by-step explanation:

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Read 2 more answers
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Step-by-step explanation:

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6 0
3 years ago
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PIT_PIT [208]
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Lubov Fominskaja [6]

Answer:

22.5 miles

Step-by-step explanation:

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7.5 x 3=22.5 miles.

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