3 years ago

Use the triangle inequality to determine the largest angle in the figure HELP!

Mathematics

2 answers:

Anettt [7]3 years ago

7 0

I think the answer is SI

mestny [16]3 years ago

4 0

Sl hopefully this helps you

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Help brainliest and 10 points

evablogger [386]

A= 1
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4 0

3 years ago

Read 2 more answers

~Can someone please help me with these questions?~

konstantin123 [22]

Answer:

the answer is B, complementary angles

Step-by-step explanation:

complementary angles are two angles that add up to 180 degrees

105 + 75 = 180

8 0

3 years ago

Which sets of side lengths represent Pythagorean triples? Check all that apply.

marshall27 [118]

Answer:

08, 15, 17

Step-by-step explanation:

Use the Pythagorean theorem.

Where the sum of both legs squared is equal to the hypotenuse squared.

8² + 15² = 17²

64 + 225 = 17²

289 = 17²

289 = 289

The side lengths that represent Pythagorean triplets are 08, 15, 17.

8 0

3 years ago

What is the solution to the equation 2x+4 - 12 = 20?<br> O X=0<br> O X=1<br> O X= 2<br> O X=9

Alex Ar [27]

Answer:

x = 14

Step-by-step explanation:

2x+4 - 12 = 20

2x - 8 = 20

2x = 28

x = 14

5 0

3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

4 0

3 years ago