Ask question

Ask question

All categories

3 years ago

15

The LA Dodgers hit the most home runs in 2014. The number of home runs accounted for 6% of the entire major league baseball home

run count. If 583 total home runs were hit, then approximately how many did the LA Dodgers hit?

1 answer:

meriva3 years ago

5 0

Answer: 39

Step-by-step explanation:

6% = .06 so .06 multiplied by 583 is 38.98 rounded is 39

You might be interested in

Under his cell phone plan, Nathan pays a flat cost of $36 per month and $3 per gigabyte. He wants to keep his bill under $45 per

victus00 [196]

Answer:

Is there a way you can add an image?

Step-by-step explanation:

3 0

3 years ago

To do his homework for a drafting class, Axel needs a round table with an area of at least 45ft. What is the area of his parent’

Natasha2012 [34]

Answer:

About 38.48ft

Step-by-step explanation:

A= $\pi$ $r^{2}$

A= $3.5^{2}$ $\pi$

A≈38.48

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B686x%5E4%20y%5E7%7D" id="TexFormula1" title="\sqrt[3]{686x^4 y^7}" alt="\sqrt

Sergio [31]

This answer is there in picture

5 0

3 years ago

A triangle has vertices at (1,3),(2,-3), and (-1,-1). What is the approximate perimeter of the triangle? A. 16 B: 14 C: 15 D: 10

Brut [27]

Answer:

B 14

explanation:

i did the math

4 0

3 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

3 years ago