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3 years ago

15

The LA Dodgers hit the most home runs in 2014. The number of home runs accounted for 6% of the entire major league baseball home

run count. If 583 total home runs were hit, then approximately how many did the LA Dodgers hit?

1 answer:

meriva3 years ago

5 0

Answer: 39

Step-by-step explanation:

6% = .06 so .06 multiplied by 583 is 38.98 rounded is 39

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A pillar is 15 m high the diameter is 84 cm what is the surface area

NARA [144]

Answer:

1416 cm

Step-by-step explanation:

Use calcutor shows everthinh

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2 years ago

an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

Hitman42 [59]

We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total.

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3 years ago

Y= sqrt(8 x^3 as it reaches the point (2, 4, the y-coordinate is increasing at a rate of 5 cm/s. how fast is the x-coordinate of

AysviL [449]

Y = √8x³

dy/dt = 2√2 * 3/2 * √x * dx/dt
⇒ 5 = 2√2 * 3/2 * √2 * dx/dt
⇒ 5 = 6 dx/dt
⇒dx/dt = 5/6 cm/s

x coordinate is changing at 5/6 cm/s

Hope it helps!

6 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

5. A new car is offered for lease for $291 per month for

Elodia [21]

Answer: B

$10,390.75

Step-by-step explanation:

Given that the lease = $291 per month

Lease pay = 291 × 24 = $6984

Time = 24 months

down payment = $458.

The lease allows for 12,000 miles per year and includes a $0.35 per mile charge for miles driven in excess of that amount.

For the car to be driven a total of 32,425 miles.

Excess = 32425 - 24000 = 8425 miles

Charges = 0.35 × 8425 = $2948.75

The cost for two years for this vehicle will be

2948.75 + 458 + 6984 = $10390.75

4 0

3 years ago