Answer:
The 95% confidence interval for the difference between proportions is (-0.046, 0.713).
Step-by-step explanation:
We want to calculate the bounds of a 95% confidence interval.
For a 95% CI, the critical value for z is z=1.96.
The sample 1 (small cars), of size n1=12 has a proportion of p1=0.6667.
![p_1=X_1/n_1=8/12=0.6667](https://tex.z-dn.net/?f=p_1%3DX_1%2Fn_1%3D8%2F12%3D0.6667)
The sample 2, of size n2=15 has a proportion of p2=0.3333.
The difference between proportions is (p1-p2)=0.3333.
![p_d=p_1-p_2=0.6667-0.3333=0.3333](https://tex.z-dn.net/?f=p_d%3Dp_1-p_2%3D0.6667-0.3333%3D0.3333)
The pooled proportion, needed to calculate the standard error, is:
The estimated standard error of the difference between means is computed using the formula:
Then, the margin of error is:
![MOE=z \cdot s_{p1-p2}=1.96\cdot 0.1935=0.3793](https://tex.z-dn.net/?f=MOE%3Dz%20%5Ccdot%20s_%7Bp1-p2%7D%3D1.96%5Ccdot%200.1935%3D0.3793)
Then, the lower and upper bounds of the confidence interval are:
![LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.3333-0.3793=-0.046\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.3333+0.3793=0.713](https://tex.z-dn.net/?f=LL%3D%28p_1-p_2%29-z%5Ccdot%20s_%7Bp1-p2%7D%20%3D%200.3333-0.3793%3D-0.046%5C%5C%5C%5CUL%3D%28p_1-p_2%29%2Bz%5Ccdot%20s_%7Bp1-p2%7D%3D%200.3333%2B0.3793%3D0.713)
The 95% confidence interval for the difference between proportions is (-0.046, 0.713).