Answer:
Angle-Angle-Side (AAS)
Step-by-step explanation:
Given triangles; ΔABD and ΔCBD
<A = <C = 
(right angle property)
AB ║ DC (given)
Then,
DA ║ CB
<B ≅ <D (congruent property)
DB ≅ BD (similarity property)
<D + <B = <B + <D (complementary angles, and property of triangles)
Therefore by Angle-Angle-Side (AAS),
∆ABD ≅ ∆CBD
Answer:
Quadrant 2
Step-by-step explanation:
Sin = opp/hyp and opp is positive in quadrants 1 & 2.
Tan = opp/adj - we need one of these values to be positive and the other negative. adj is negative in quadrants 2 & 3.
Quadrant 2 is found in both of the scenarios that we need to occur.
We can put the two equations together with substitution, and we get
3x + 2y = 30
Now we have a single equation in two variables, so we don't have enough information to solve for both x and y.
A rectangle, presumably, as the cross section is going to be whatever shape the outward faces are (in the case of a vertical cross section like this one)
I don’t really know it sry
