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1.326 grams of NH3 are required to produce 4.65 g of HF.
Step-by-step explanation:
Balanced chemical reaction is written first to know the number of moles taking part in original reaction.
NH3 +3 F2 ⇒3 HF + NF3
Given:
mass of HF = 4.65
First the number of moles of HF in 4.65 grams is calculated by using the formula:
number of moles (n) =
atomic mass of HF = 20 grams/mole
putting the values in the above equation number of moles can be found.
n =
= 0.235 moles of HF are given.
From the equation it can be said that:
1 mole of NH3 reacts to form 3 moles of HF
so, x moles of NH3 would react to form 0.235 moles of HF
=
3x = 0.235
x =
x = 0.078 moles of NH3 is required.
The moles are converted to mass by applying the formula:
mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)
putting the values in the formula
mass = 17 X 0.078
mass = 1.326 grams
ANSWER
where,
EXPLANATION
We want to simplify the rational expression
We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares
We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,
We now factor to obtain,
This implies that,
We now cancel out common factors to obtain,
The restriction is that, the denominator cannot be zero.
Thus
This implies that,
where,
EXPLANATION
We want to simplify the rational expression
We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares
We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,
We now factor to obtain,
This implies that,
We now cancel out common factors to obtain,
The restriction is that, the denominator cannot be zero.
Thus
This implies that,