Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer:
1=1
2=4
3= <NTR=115
<RTM=45
<STN=45
4= A-124
B-45
C-45
D-90
E-124
5=15
6=?
Step-by-step explanation:
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Check the picture below.
since the distance AB cannot be a negative value, thus is not -3-√(130).
Answer: 2 - 4x = 6
Please mark me as brainliest
Answer: c
Step-by-step explanation:
