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3 years ago

WILL GIVE BRAINLIEST!!!! How much fat is in a mixture created with x pints of 8% butterfat and y pints of 15% butterfat?

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Step-by-step explanation:

Total fat in mixture is 8x+15y100 pints.

Explanation:

In a mixture of x pints of 8% butterfat, we have 8x100 pints of butter

and in y pints of 15% butterfat, we have 15y100 of butterfat.

Hence total fat in mixture is 8x+15y100 pints.

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2 years ago

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3 years ago

If f(x) = 3LX-2], what is f(5.9)? 9 10 11 12

Black_prince [1.1K]

Answer: 12

Step-by-step explanation:

We know that , the ceiling function y = [x] is also known as the least integer function that gives the smallest integer greater than or equal to x.

For example : For x= 1.5

y = [1.5] =2

For x= 3.64

y = ⌊3.64⌋=4

The given function :

Then, for x= 5.9 , we have

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2 years ago

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3 years ago

A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.

Tanzania [10]

Answer: The height of the container is 10 centimeters. If its diameter and height were both doubled, the container's capacity would be 8 times its original capacity.

Step-by-step explanation:

The volume of a cone can be calculated with this formula:

$V=\frac{\pi r^2h}{3}$

Where "r" is the radius and "h" is the height.

We know that the radius is half the diameter. Then:

$r=\frac{12cm}{2}=6cm$

We know the volume and the radius of the conical container, then we can find "h":

$120\pi cm^3=\frac{\pi (6cm)^2h}{3}\\\\(3)(120\pi cm^3)=\pi (6cm)^2h\\\\h=\frac{3(120\pi cm^3)}{\pi (6cm)^2}\\\\h=10cm$

The diameter and height doubled are:

$d=12cm*2=24cm\\h=10cm*2=20cm$

Now the radius is:

$r=\frac{24cm}{2}=12cm$

And the container capacity is

$V=\frac{\pi (12cm)^2(20cm)}{3}=960\pi cm^3$

Then, to compare the capacities, we can divide this new capacity by the original:

$\frac{960\pi cm^3}{120\pi cm^3}=8$

Therefore, the container's capacity would be 8 times its original capacity.

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2 years ago

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