All categories

3 years ago

Please I really need this fast Find the values of a and b in the kite below.

Mathematics

1 answer:

Marina CMI [18]3 years ago

5 0

Answer:

a=5, b=15

Step-by-step explanation:

we know that

The figure MNLO is a Kite

LO=NO and MN=LM

we have

LO=7a-14, NO=b+6

7a-14=b+6 -----> equation A

MN=b, LM=3a

b=3a -----> equation B

Solve the system of equations by substitution

Substitute equation B in equation A and solve for a

7a-14=(3a)+6

7a-3a=6+14

4a=20

a=5

Find the value of b

b=3a ----> b=3(5)=15

therefore

a=5, b=15

You might be interested in

Look at points C and D on the graph:

anyanavicka [17]

I think C Tell me if I’m wrong

7 0

3 years ago

Read 2 more answers

Please help me with the Math. Thx in advance! <br> Number's 8-11. THANK YOU!

Stella [2.4K]

8 :=7
9= 2/3
10=3/20
11=4

8 0

3 years ago

Read 2 more answers

Which values are solutions to K-3 >-2? Select two options.

Ierofanga [76]

Step-by-step explanation:

k‒3>‒2=k>‒2+3

=k>1

so there is not the answer here

5 0

3 years ago

Describe how k affects the graph of the function f(x)= -3/5(10)^x

Shalnov [3]

Answer:

1437.33

Step-by-step explanation:

8 0

3 years ago

Simplify the following radical <br> Sqrt 126x^13

fenix001 [56]

Answer:

$\large\boxed{\sqrt{126x^{13}}=3x^6\sqrt{14x}}$

Step-by-step explanation:

$Domain:\ x\geq0\\\\\sqrt{126x^{13}}=\sqrt{9\cdot14\cdot x^{12+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{9\cdot14\cdot x^{12}\cdot x^1}=\sqrt{9\cdot14\cdot x^{6\cdot2}\cdot x}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{and}\ (a^n)^m=a^{nm}\\\\=\sqrt9\cdot\sqrt{14}\cdot\sqrt{(x^6)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=3\cdot\sqrt{14}\cdot x^6\cdot\sqrt{x}=3x^6\sqrt{14x}$

3 0

3 years ago