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3 years ago

1 3 4 0.5 - 3 - 6.5 - 10 What is the linear function?

Mathematics

1 answer:

Wewaii [24]3 years ago

7 0

Answer: it’s probably negative 6.5 but there has to be a grid to be more clear

Step-by-step explanation:

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If three times a number is minus

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Another number will be negative.

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3 years ago

A coin will be tossed 100 times. You get to pick 11 numbers. If the number of heads turns out to equal one of your 11 numbers, y

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2 years ago

Katie buys a large pizza for $14.99 and bottles of soda for $1.50 each. If the total cost was $23.99, how many bottles of soda (

Nady [450]

The number of soda bottles Katie bought is 6

The given parameters are:

Large Pizza = $14.99
Soda = $1.50 per bottle
Total cost = $23.99

Assume the number of soda bottle is x.

So, we have:

$Total = Pizza + Soda \times x$

This gives

$23.99 = 14.99 + 1.50\times x$

Subtract 14.99 from both sides of the equations

$9 = 1.50\times x$

Divide both sides of the equations by 1.5

$6=x$

Rewrite the equation as

$x = 6$

Hence, the number of bottles is 6

Read more about linear equations at:

brainly.com/question/14323743

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2 years ago

In the number 514,482,441, how is the relationship between the first pair of 4s the same as the relationship between the second

yanalaym [24]

In the 1st pair of fours the 4 on the left side is 10 times greater than the 4 on the right. The same thing with the 2nd pair of fours. The 4 on the left side is 10 greater than the 4 on the right. Hope this helps!

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3 years ago

Read 2 more answers

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10

$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$

3 0

2 years ago