Answer:
ill start figuring it out now luv <3
Step-by-step explanation:
3(2x+1)=2(x+1)+1
Step 1:Simplify both sides of the equation
(3)(2x)+(3)(1)=(2)(x)+(2)(1)+ -(distribute)
6x+3=2x+2+1
6x+3=(2x)+(2+1) -(Combine Like Terms)
6x+3=2x+3
Step 2: Subtract 2x from both sides
6x+3-2x=2x+3-2x
4x+3-3=3-3
4x÷4=0÷4
x=0
<h2><u>Problem</u>:-</h2>
2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method.
<h2><u>Solution</u>:-</h2>
<h2><u>Answer</u>:-</h2>
- The zeros of y = x² – 3x + 2 are 2 and 1.
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#CarryOnLearning
(ノ^_^)ノ