3 years ago

Find element a13 of matrix A, if A=

Mathematics

1 answer:

astraxan [27]3 years ago

8 0

$\bf \begin{bmatrix} 2&-3&\boxed{4}\\ 5&0&-6\\ 7&2&-8 \end{bmatrix}\impliedby a_{1,3}\textit{ row 1, column 3}$

You might be interested in

To verify the identity tan (x1+x2+x3) = tan x1 + tan x2 + tan x3 - tan x1 tan x2 tan x3 / 1 - tan x1 tan x2 - tan x2 tan x3

andrezito [222]

Answer:

The answer is the last one

$tan(x_{1}+x_{2}+x_{3})=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

Step-by-step explanation:

∵ $tan(x_{1}+x_{2}+x_{3}=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

$=\frac{tanx_{1}+\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}} }{1-tanx_{1}(\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}})}$

Multiply up and down by $1-tanx_{2}tanx_{3}$

$\frac{tanx_{1}(1-tanx_{2}tanx_{3})+tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}-tanx_{1}tanx_{2}-tanx_{1}tanx_{3}}$

$=\frac{tanx_{1}+tanx_{2}+tanx_{3}-tanx_{1}tanx_{2}tanx_{3}}{1-tanx_{1}tanx_{2}-tanx_{2}tanx_{3}-tanx_{1}tanx_{3}}$

7 0

3 years ago

Read 2 more answers

30 people liked Brand X. This is 20% of the people in a survey.

Yuki888 [10]

A) 150 people
b) 80%
c) 120 people

3 0

3 years ago

Write 240 minutes in hours

miv72 [106K]

240 minutes is equal to 4 hours.

7 0

3 years ago

Read 2 more answers

17,985 + -33,789. i really need this question answered

nikdorinn [45]

Answer:

-15804

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Jose substitutes a value for y in the equation 5y = 3y + 4

sesenic [268]

Answer:

Step-by-step explanation:

Equation

5y = 3y + 4

combine like terms 3y becomes negative when moved to the left side being that its positive on the right. 4 has no variable so it stands alone on the right side.

-3y + 5y = 4

After adding a low negative to a high positive number. Turns into 2y.

2y = 4

Divide 2 on both sides to remove the number from the variable on the left.

$\frac{2}{2}$ y = $\frac{4}{2}$

2 is canceled on the left side which gives the solution for Y.

y = 2

5 0

3 years ago

Read 2 more answers