What is the equation of the line that passes through the point (-6,6) and has a
slope of 1/3?
1 answer:
Answer:
Explanation:
y-y = m(x - x)
I couldn't tell if the point was negative, so I'll do both
Positive Negative
(6,6) m= 1/3 -(6,6) m= 1/3
y-6 = 1/3(x - 6) y+6 = 1/3(x +6)
y-6 = 1/3x - 2 y+6 = 1/3x + 2
y = 1/3x +4 y = 1/3x - 4
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