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tresset_1 [31]
3 years ago
5

Solve for x. round to the nearest tenth

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

<em>hi</em><em> </em><em>I</em><em> </em><em>am</em><em> </em><em>interested</em><em> </em><em>for</em><em> </em><em>your</em><em> </em><em>post</em><em> </em><em /><em> </em><em>☺</em><em> </em><em /><em> </em><em>✨</em><em> </em><em /><em> </em><em /><em> </em><em>I</em><em> </em><em>am</em><em> </em><em>interested</em><em> </em><em>to</em><em> </em><em>apply</em><em> </em><em>to</em><em> </em><em>join</em><em> </em><em>your</em><em> </em><em>company</em><em> </em><em /><em> </em><em>☺</em><em> </em><em>and</em><em> </em><em>simplify</em><em> </em><em>I</em><em> </em><em>am</em><em> </em><em>working</em><em> </em><em /><em> </em><em /><em> </em><em>I</em><em> </em><em>am</em><em> </em><em>working</em><em> </em><em>for</em><em> </em><em>a</em><em> </em><em>company</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em /><em> </em><em /><em> </em><em /><em> </em><em>☺</em><em> </em><em /><em> </em><em>and</em><em> </em><em>simplify</em><em> </em><em>are</em><em> </em><em>some</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>my</em><em> </em><em>dear</em><em> </em><em /><em> </em><em /><em> </em><em /><em> </em><em>❤</em><em> </em><em>☺</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>factor</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>subtract</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>following</em><em> </em><em /><em> </em><em /><em> </em><em /><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>my</em><em> </em><em>friend</em><em> </em><em>who</em><em> </em><em>has</em><em> </em><em>issue</em><em> </em><em /><em> </em><em /><em> </em><em>and</em><em> </em><em>a</em><em> </em><em>speedy</em><em> </em><em>response</em><em> </em><em>from</em><em> </em><em>you</em><em> </em><em>and</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>not</em><em> </em><em>received</em><em> </em><em /><em> </em><em /><em> </em><em>for</em><em> </em><em>my</em><em> </em><em>last</em><em> </em><em>year</em><em> </em><em>since</em><em> </em><em>I</em><em> </em><em>was</em><em> </em><em>a</em><em> </em><em>sequence</em><em> </em><em>and</em><em> </em><em>simplify</em><em> </em><em>and</em><em> </em><em>simplify</em><em> </em><em>in</em><em> </em><em>my</em><em> </em><em>team</em><em> </em><em>and</em><em> </em><em>simplify</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>team</em><em> </em><em /><em> </em><em /><em> </em><em>the</em><em> </em><em>first</em><em> </em><em /><em> </em><em /><em> </em><em>❤</em><em> </em><em /><em> </em><em /><em> </em><em>☺</em><em> </em><em /><em> </em><em /><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>numbers</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>few</em><em> </em><em>weeks</em><em> </em><em /><em> </em><em /><em> </em><em>❤</em><em> </em><em /><em> </em><em /><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>factor</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>subtract</em><em> </em><em>and</em><em> </em><em>is</em><em> </em><em>very</em><em> </em><em>much</em><em> </em><em /><em> </em><em /><em> </em><em /><em> </em><em>❤</em><em> </em><em /><em> </em><em>☺</em><em> </em><em /><em> </em>

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A hot dog costs $1 at the ballpark. Which equation shows the total cost, C, of n hot dogs?
pochemuha
C=1n is the answer because the cost of hotdogs equals the price times the number of hotdogs
5 0
2 years ago
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Solve For X Help me please
Lapatulllka [165]

Answer is A

Once you add 29 to negative 34 you will get negative 5 and then divide 5 and you will end up with negative 1 always flip the sign when dealing with a negative

3 0
3 years ago
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A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

6 0
3 years ago
Enter the correct number word to complete the conversion. 1 milliampere = one ? of an ampere
Lerok [7]

Answer:

One milliampere is equal to 0.001 ampere.

Step-by-step explanation:

Mili, refers to thousandth. (for example, millimeter or milliliter.)

6 0
3 years ago
Help with the first section and second please. Also add explanation, or step by step. Thanks!
shepuryov [24]
<h3>1)</h3>

• 6x -2(x -5) = -2 . . . . given

• 6x -2x +10 = -2 . . . . X Cameron errored here. When multiplying -2 by -5, the result is 10, not -10.

• 4x +10 = -2 . . . . . . x terms are correctly collected

• 4x +10 -10 = -2 -10 . . . . add the opposite of the constant on the left

• 4x/4 = -12/4 . . . . divide by the x-coefficient

• x = -3 . . . . . . . . . . simplify

<h3>2)</h3>

• 11x -10 = -34 . . . . combine like terms

• 11x -10 +10 = 34 +10 . . . . addition property of equality

• 11x = 44 . . . . . . . . simplify

• 11x/11 = 44/11 . . . division property of equality

• x = 4 . . . . . . . . . . . simplify

7 0
3 years ago
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