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Wittaler [7]
3 years ago
11

SEE QUESTION IN IMAGE

Mathematics
1 answer:
shtirl [24]3 years ago
8 0

Answer:

  • d) 2y + x = 106

Step-by-step explanation:

<u>Mean of the data = sum of the data / number of frequencies:</u>

  • (40 + 38 + y + y + x + 32)/6 = 36
  • 2y + x + 110 = 36*6
  • 2y + x = 216 - 110
  • 2y + x = 106

Correct choice is d

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Keeps 7. White T- Shirts on the shelves for every purple T-Shirts on the shelves How many white t-shirts on the shelves if you h
aalyn [17]
If you have 7:1 ratio of white to purple shirts and you have 15 purple shirts, you have to do 7*15 =105 to find that if you had 15 purple shirts you would have 105 white shirts
8 0
3 years ago
What is the lowest number (not including 1) that is a triangular number and a<br> square number?
Yuliya22 [10]

Answer:

0

Step-by-step explanation:

0 1 36 1225 are triangle and square no

5 0
3 years ago
-7x- 8y=9<br>4x +9y=-22​
BlackZzzverrR [31]

Answer:

(95/31, -118/31)

Step-by-step explanation:

-7x-8y=9

4x+9y=-22

----------------

4(-7x-8y)=4(9)

7(4x+9y)=7(-22)

-----------------------

-28x-32y=36

28x+63y=-154

-----------------------

31y=-118

y=-118/31

-7x-8(-118/31)=9

-7x+944/31=9

-7x=9-944/31

-7x=279/31-944/31

-7x=-665/31

7x=665/31

x=(665/31)/7

x=(665/31)(1/7)

x=665/217=95/31

x=95/31, y=-118/31

5 0
3 years ago
Y''-2y'+y=2(e^x)-3(e^-x)
labwork [276]
First find the characteristic solution. The characteristic equation is

r^2-2r+1=(r-1)^2=0

which as one root at r=1 of multiplicity 2. This means the characteristic solution for this ODE is

y_c=C_1e^x+C_2xe^x

For the nonhomogeneous part, you can try a particular solution of the form

y_p=(a_2x^2+a_1x+a_0)e^x+be^{-x}

which has derivatives

{y_p}'=(a_2x^2+(2a_2+a_1)x+a_1+a_0)e^x-be^{-x}
{y_p}''=(a_2x^2+(4a_2+a_1)x+2a_2+2a_1+a_0)e^x+be^{-x}

Substituting into the ODE, the left hand side reduces significantly to

2a_2e^x+4be^{-x}=2e^x-3e^{-x}

and it follows that

\begin{cases}2a_2=2\\4b=-3\end{cases}\implies a_2=1,b=-\dfrac34

Therefore the particular solution is

y_p=x^2e^x-\dfrac34e^{-x}

and so the general solution is the sum of the characteristic and particular solutions,

y=y_c+y_p
y=C_1e^x+C_2xe^x+x^2e^x-\dfrac34e^{-x}
3 0
3 years ago
PLEASE PLEASE PLEASE HELP
Rudiy27

Answer:

Yes because they are all have a point at  where they meet

Step-by-step explanation:

6 0
4 years ago
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