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Chlorine goes from Cl₂ to ClO⁻.
Oxidation state of Cl in Cl₂ is zero whereas in ClO⁻ it is +1. Hence change in oxidation state of Chlorine is 1.
Calculation of oxidation number of Cl in ClO⁻ or HClO⁻ :
Let x be oxidation number of Cl in ClO⁻ the. Now since the net charge on ClO⁻ is -1, sum of oxidation number of all must be equal to -1.
Therefore,
x + (-2) = -1 .....[ oxidation number of O is -2]
∴ x = 2-1 = +1
Therefore oxidation number of Cl in ClO⁻ is +1
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<h3>
Answer:</h3>
23 grams Na
<h3>
Explanation:</h3>
- Molarity is the concentration of a solution in moles per liter.
- Therefore, a solution with a molarity of 3M contains 3 moles of solute in 1 liter of solution, while a solution with 2M contains 2 moles of solute in 1 liter of solution.
Thus, 3 M = 3 moles/liter
2 M = 2 moles /liter
The difference is 1 mole/Liter
But, 1 mole of sodium 23 g
Therefore;
Mass of sodium = moles × Atomic mass
= 1 mole × 23 g/mol
= 23 g
Therefore a 3 M solution contains 23 g of sodium more than a 2 M solution.
Answer: An Element
Explanation:
An element is a substance that cannot be split into smaller substance. It is made up of one kind of atom and can exist either as molecules (e.g nitogen) or an atom (e.g argon).