Answer:
B) -1551 kJ
Explanation:
There are two heat flows in this question.
Heat released by engine + heat absorbed by water = 0
q₁ + q₂ = 0
q₁ + mCΔT = 0
Data:
m = 2.51 kg
C = 3.41 J°C⁻¹g⁻¹
T_i = 23.8 °C
T_f =205 °C
Calculations:
(a) ΔT
ΔT = 205 °C - 23.8 °C = 181.2 °C
(b) q₂
q₂ = mCΔT = 2510 g × 3.41 J·°C⁻¹g⁻¹ × 181.2 °C = 1.551× 10⁶ J = 1551 kJ
(c) q₁
q₁ + 1551 kJ = 0
q₁ = -1551 kJ
What compound are you trying to show
