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3 years ago

12

Student enrollment at a local school last year was 15% higher than this year. This year, 620 students are enrolled. How many stu

dents were enrolled last year?

1 answer:

Assoli18 [71]3 years ago

5 0

Answer:

713 students were enrolled last year

Step-by-step explanation:

620 + 15%

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Please answer correctly !!!!!!!!!!!!! Will mark Brianliest pleaseeeee !!!!!!

Dimas [21]

Answer:

2sqrt(10)

Step-by-step explanation:

Use the Pythagorean theorem.

x^2 + 3^2 = 7^2

x^2 + 9 = 49

x^2 = 40

x = sqrt(40)

x = 2sqrt(10)

7 0

3 years ago

30 points plus brainliest if you get it right with step by step explanation.

Leto [7]

Answer:

a. 150

b. y=150x+1200

Step-by-step explanation:

a. 1350-1200=150

b. if he opened it in 2005 he started his tutoring fee at 1200 that makes 1200 the y intercept

8 0

3 years ago

Given that (x+2) is a factor of x^3+8, find the other quadratic factor.

Semmy [17]

If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4

3 0

3 years ago

If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?

Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20 </u> * <u> 20 </u>* <u> 20 </u> *<u> 20 </u>* <u> 20 </u>

First number 2nd number 3rd number 4th number 5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are $20^{5}$ ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15 </u> * <u> 15 </u>* <u> 15 </u> *<u> 15 </u>* <u> 15 </u>

First number 2nd number 3rd number 4th number 5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are $15^{5}$

So the probability P can be calculate as:

$P=\frac{15^{5} }{20^{5} } \\P=0.2373$

Then the probability that their minimum is larger than 5 is 0.2373

7 0

3 years ago

Howdo i find a rate of two numbers?

harina [27]

I don't know if you can find a rate with 2 numbers. You can find a rate with 2 sets of numbers. If you only have 2 numbers you cannot do much.

however if the problem says something like x changed from 45 to 65 over some x values that are not given you can find the rate. this is because you are actually given 2 sets of numbers. It it doesn't have to be x and y. It could say it another way. let's say it says you get on the freeway at 45 mph and when you see yout exit sign you are traveling 65 mph. What is your rate of change. this can actually be written in (x,y) form. in both of these examples you can say (x1, 45) and (x2, 65).

well the rate of change would just be the difference in y values per the difference in x values. If you think about it, this is just the slope of the line it creates. (y2 - y1) / (x2 - x1).
or:
(64 - 45) / (x2 - x1).
20 / (x2 - x1).

this can be worded as we had a rate of change of 20 per (x2 - x1) time period.

or you could say out rate of change was just 20 if of the time period is already understood.

i hope this helps. I am not sure if it was what you were asking

5 0

4 years ago