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solniwko [45]
3 years ago
6

Benji, a 12 kg Border terrier, requires daily injections of ampicillin 15% for 3 days. The dose rate is 7.5

Mathematics
1 answer:
pogonyaev3 years ago
6 0
<h2>Hello!</h2>

The answer is:

Benji requires 90mL per injection.

<h2>Why?</h2>

From the statement we know that dog's weight is 12 kg, and daily injections are required for 3 days, the dose rate is 7.5 mg/kg, so we need to calculate how many mL per injection does Benji require.

We have that:

Weight=12Kg\\\\Dose=7.5\frac{mL}{Kg}

If the dose rate is 7.5 mL per each Kg, how many mL are required for 12 Kg? We can set it up using the following relation:

7.5mL=1Kg\\x=12Kg\\\\x=\frac{7.5mL*12Kg}{1Kg}=\frac{90mL.Kg}{1Kg}=90mL

Hence, we have that there are needed 90 mL per injection.

Have a nice day!

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4 years ago
Suppose you start with a full tank of gas (14 gallons) in your truck. After driving 4 hours, you now have 2
Alex73 [517]

Answer:

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Step-by-step explanation:

Rate of change is computed by dividing the amount of change by the interval over which it occurred.

<h3>a)</h3>

Here the amount of gas decreased from 14 to 2 gallons, so a decrease of 14-2 = 12 gallons. That occurred over a 4-hour period, so the rate of change is (-12 gallons)/(4 hours) = -3 gallons/hour.

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<h3>b)</h3>

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4 0
2 years ago
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Mars2501 [29]

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6 0
3 years ago
Please answer these with lots of detail. I want to be able to understand the topic and material well.
IRISSAK [1]

Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

If we move 1 unts right of x=0, we get f(x) = 2.

Therefore, δ can't be more than 1.

Since f(x) isn't continuous within this domain, we can't conclude that the limit exists.

Q4

(a) Yes.  If δ = 0.25, then 0.75 < x < 1.25, and f(x) > 200.

(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

(c) Yes.  If δ ≈ 0.1, then 0.9 < x < 1, and f(x) > 450.

6 0
4 years ago
Please help. What would be the proper proof for this problem? Prove: line BE congruent line BD.
Bumek [7]

Answer:

line AB is congruent to line CB . proof: given

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Step-by-step explanation:

Sorry if I'm wrong on this, but I hope you understand the general idea!

5 0
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