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Free_Kalibri [48]
3 years ago
14

A scuba diver dove 40 feet below the surface. He swam up 12 feet to see a unique fish. He followed the fish down 8 feet. Then he

followed the fish up 27 feet. How far below the surface is the diver now?
Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer: 9 feet below the surface.

Step-by-step explanation:

The scuba diver starts 40 ft below the surface. We can represent the position of the scuba diver as:

Position = -40ft

Where the negative sign is because it is below the surface of the water, so

"He swam up 12 feet to see a unique fish."

Now we need to add 12ft

Then his new position is:

Position = -40ft + 12 ft = -28ft

"He followed the fish down 8 feet.

Now we need to subtract 8ft

His new position is:

Position = -28ft - 8 ft = -36 ft

"Then he followed the fish up 27 feet."

Now we add another 27 ft.

The final position will be:

Position = -36ft + 27ft = -9ft

Then the final position of the scuba diver is -9ft, that means that he is 9 feet below the surface.

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Step-by-step explanation:

2(x+3)-4x=x

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3X+3(X+Y)

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=3x+3x+3y

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PLEASE HELPPPPPPPPPP
RUDIKE [14]

Answer:

y = 25.20 m

Step-by-step explanation:

By applying tangent rule in ΔABC,

tan(25)° = \frac{\text{Opposite side}}{\text{Adjacent side}}

             = \frac{y}{BC}

BC = \frac{y}{\text{tan}(25)} --------(1)

Now we apply tangent rule in ΔABD,

tan(15)° = \frac{y}{BC+CD}

tan(15)° = \frac{y}{BC+40}

BC + 40 = \frac{y}{\text{tan}(15)}

BC = \frac{y}{\text{tan}(15)} - 40 -------(2)

From equation (1) and (2),

\frac{y}{\text{tan}(25)}=\frac{y}{\text{tan}(25)}-40

\frac{y}{\text{tan}(25)}-\frac{y}{\text{tan}(25)}=-40

y[\frac{1}{\text{tan}(25)}-\frac{1}{\text{tan}(25)}]=-40

y(2.1445 - 3.7321) = -40

1.5876y = 40

y = 25.1953

y ≈ 25.20 m

Therefore, measure of y is 25.20 m.

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3 years ago
8.89234x10 to5 in standard form
TiliK225 [7]
8.89234* 10^{5} =8.89234* 100000 =889,234 \ \textless \ -answer
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3 years ago
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