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horsena [70]
2 years ago
10

What is the answer to (8y -6

Mathematics
1 answer:
scZoUnD [109]2 years ago
6 0

Answer:

Step-by-step explanation:

Incomplete presentation of question.  Did you want to factor out the greatest common factor (which is 2), obtaining 2(4y - 3)?  Or something else?  Also:  please note that if you use the left parenthesis ) , you MUST also use the right parenthesis ( .

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Geometry help please I'm stuck will give brainiest answer and thanks and five stars if correct
Tpy6a [65]
1. Reduction: 1/2
2. 200 millimeters
3. Glide Reflection
8 0
3 years ago
A man bought a computer on hire purchase by making a down payment of$1500 and twelve monthly payments of $250 each. calculate th
lubasha [3.4K]

Answer:

$4500

Step-by-step explanation:

Given parameters:

   Down payment = $1500

   Monthly payment for twelve months  =$250

Unknown;

Total hire purchase price  = ?

Solution:

To find the total hire purchase price;

  Total hire purchase price  = Down payment + 12($250)

  Total hire purchase price  = $1500 + $3000

  Total hire purchase price  = $4500

7 0
2 years ago
Help me with this please
Tems11 [23]

Answer:

q.4 's answer is d. miles

q.5 's answer is 3

q.6 's answer is 6

can you tell what the dot means i can tell you the other two's too

4 0
2 years ago
How many students had fewer than 5 buttons on their clothes. <br> a:9 <br> b:18 <br> c:2 <br> d:11
Bingel [31]

Answer:

D) 11

Step-by-step explanation:

If you start at five and count back on each little x

than you should come up with 11

0=3

1=1

2=2

3=4

4=1

3+1+2+4+1=11

You do This because you need to find how many has fewer so you don't count 5

3 0
3 years ago
Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ
Amanda [17]
So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

\bf \qquad \textit{Amount for Exponential change}\\\\&#10;A=P(1\pm r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{starting amount}\to &500\\&#10;r=rate\to 1\%\to \frac{1}{100}\to &0.01\\&#10;t=\textit{elapsed period}\to &300\\&#10;\end{cases}&#10;\\\\\\&#10;A=500(1-0.01)^{300}
7 0
2 years ago
Read 2 more answers
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