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AleksandrR [38]
3 years ago
9

Pls help due ASAP.... Pls show workings.

Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

We can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

  • d = 8.06 miles

Step-by-step explanation:

From the coordinate plane, we can clearly identify that:

  • Sandy's Hotel is located at the point (-8, 9)
  • Trader Joes' Store is located at the point (-4, 2)

The distance from Sandy's Hotel to Trader Joes' Store can be calculated such as:

d=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

The distance between (-8, 9) and (-4, 2)

d=\sqrt{\left(-4-\left(-8\right)\right)^2+\left(2-9\right)^2}

  =\sqrt{\left(-4+8\right)^2+\left(2-9\right)^2}

  =\sqrt{4^2+7^2}  

   =\sqrt{16+49}

    =\sqrt{65}

    =8.06 miles

Therefore, we can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

  • d = 8.06 miles
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