(x-1)(x-1) + (y+2)(y+2) = 3
x2 -1x -1x + 1 + y2 +2y +2y +4=3
x2 +y2 -2x +4y + 2=0
A is the answer
Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 
Sa= 1.64
(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!
Answer: Hello daema, let's let x be the goal and c be the collection per day.
x - 45 + c = x + 5 is the answer so now let's talk about how we did that.
So she wants to get to x which is the goal. But right now she has 45 less than what her goal is. So that would look like this x - 45 now she has to get c or the collection per day to get to her goal. So now it looks like this x - 45 + c. Now that c has to be at least x which is her goal, it now will look like this x - 45 + c = x. But we're not done, the question said that now she 5$ over her goal, or x. So we have to add the + 5 onto the end so now it looks like this x - 45 + c = x + 5. To solve the equation "if you have to" it would be x = 50$ per day.
Spencer??
LIKE THE NOVEL "PRETTY LITTLE LIARS"????
OMG I LOVE SPENCER IS ONE OGF MY FAVORITE LOL sorry..
umm well she use this method:
1/3. 4/1
4/3
4
that's it lol .... :v
