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gladu [14]
3 years ago
5

There are types of templates​

Computers and Technology
1 answer:
guajiro [1.7K]3 years ago
3 0
You didn’t explain your question correctly so I can’t help you
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Which of the following is NOT one of the MOST common uses of Twitter?
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Which of the following is NOT one of the MOST common uses of Twitter? b . Making a business contact.
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A ____________would be a misconfiguration of a system that allows the hacker to gain unauthorized access, whereas a_____________
seraphim [82]

Answer:

The answer to this question is vulnerability and risk.

Explanation:

Vulnerability is there us misconfiguration in the system  and we know that our system is vulnerable means the hacker can gain unauthorized access to our system.

Risk is when there are chances that a misconfiguration  might happen in our system in future so that hacker could gain unauthorized access to the system.

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Small-business owner Marcos set up his Google Ads campaign by thinking of “obvious” keywords off of the top of his head. What's
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Jonathan works with a team of graphic designers. They have a collection of images and have divided the image editing work among
kondaur [170]

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4 years ago
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In this lab, you use what you have learned about searching an array to find an exact match to complete a partially prewritten C
icang [17]

Answer:

Complete the program as follows:

for(int i = 0; i<10; i++){

     if(inCity == citiesInMichigan[i]){

         foundIt = true;

         break;       }    }

   if(foundIt){         cout<<"It is a city";     }

   else{         cout<<"Not a city";     }

Explanation:

Required

Complete the pre-written code in C++ (as indicated by the file name)

The pre-written code; though missing in this question, can be found online.

The explanation of the added lines of code is as follows:

This iterates through the array

for(int i = 0; i<10; i++){

This checks if the city exists in the array

     if(inCity == citiesInMichigan[i]){

If yes, foundIt is updated to true

         foundIt = true;

And the loop is exited

         break;       }    } -- The loop ends here

If foundIt is true, print it is a city

<em>    if(foundIt){         cout<<"It is a city";     }</em>

Print not a city, if otherwise

<em>    else{         cout<<"Not a city";     }</em>

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3 years ago
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