Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms
by 1. we eliinate 2nd one
by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder
thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9
last one is answer
Answer:
do you have to add the numbers together or multiply
Answer:
$1.75
Step-by-step explanation:
The selling for each candy bar may be determined by a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.
It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation
.
Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25
23s + 36c = 114.75
37s + 36c = 146.25
14s = 31.5
s = $2.25
23(2.25) + 36c = 114.75
36c = 114.75 - 51.75
36c = 63
c = 63/36
= $1.75
Answer:
probability that Caroline buy both CD and fruit = 0.52
Step-by-step explanation:
We have given that the probability of Caroline buys a fruit P = 0.4
So probability of Caroline does not buy the fruit = 1 - 0.4 = 0.6
Probability Caroline buys a CD P = 0.2
So probability of Caroline does not buy the CD = 1 - 0.2 = 0.8
So probability that Caroline does not buy either buy CD or fruit = 0.8×0.6=0.48
So probability that Caroline buy both CD and fruit =1-0.48 = 0.52
Answer:
Option D. 7/250 = 24.8/x; 885.71
Step-by-step explanation:
we know that
Using proportion
