165 divided by 11 equals 15
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
Step-by-step explanation:
first cirscross it come 2nˆ4X=3L4mˆ2and divide each by 2nˆ4 to make X alone and it come, X=3L4mˆ2/2nˆ4. try my best ,if i am wrong tell me.
The volume of the shaded part in cubic units is 4/3π(20)³ - 4/3π(4)³
<h3>Volume of composite object</h3>
The sphere is a a solid 3-dimensional object. THe formula for calculating its volume is expressed as:
V = 4/3πr³
where:
r is the radius of the sphere
<u>For the outer sphere:</u>
V = 4/3π(20)³
<u>For the inner sphere:</u>
V = 4/3π(4)³
The volume of the shaded part in cubic units is 4/3π(20)³ - 4/3π(4)³
Learn more on volume of sphere here: brainly.com/question/10171109
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The answer to the first part of your question is 9
as for the second part 36/4 (which is 9 btw) then subtract 2 I answered this one the best I could (let me know if I'm wrong)
(i just don't have to much time on my hands because I have homework myself)
