Find the equation of the linear function represented by the table below in slope-

Mathematics

1 answer:

ElenaW [278]3 years ago

7 0

Answer:(5,48)

Step-by-step explanation:

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What is the vertex of the graph y= x^2 + 6x - 5

Rashid [163]

we are given

$y= x^2 + 6x - 5$

Firstly ,we can find equation in vertex form

so, we will complete x square

$y= x^2 + 6x+3^2-3^2 - 5$

$y= (x+3)^2-3^2 - 5$

$y= (x+3)^2-14$

now, we can compare it with vertex form of equation

$y= (x-h)^2+k$

we can find h and k

$h=-3 , k=-14$

so, vertex is

$(h,k)=(-3,-14)$ .............Answer

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3 years ago

Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to

MArishka [77]

I hope this helps you

slope = 5-0/-6-(-3)= -5/3

(0,0)

m.(x1-x)=y1-y

-5/3.(0-x)=0-y

5x= -3y

5x+3y=0

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4 years ago

Point a (–4,1) is in the standard ( x , y ) co ordinate pl an

ser-zykov [4K]

The line x = 2 is vertical. This means that ab is horizontal since they are perpendicular. So, the y coordinate of b must be 1.

If x = 2 bisects ab, then a and b are equal distances from x = 2.

a is 2 - (-4) = 6 units away from x = 2, so b must be 6 units away in the other direction. The x coordinate of b is 6 + 2 = 8.

The coordinate of b is (8, 1)

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4 years ago

Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the s

Furkat [3]

Answer:

$\frac{16\pi}{3}$ .

Step-by-step explanation:

I graphed the region in the image below. The blue line is y=3, the purple line is x=1 and the green curve is y = $4x-x^{2}$ . The shaded region in blue is the region we are going to rotate.

Now, to find the volume v= $2\pi \int\limits^a_b {p(x)h(x)} \, dx$ where a=1, b=3 (left and right points of the region), p(x) is the distance from the rotation axis to the diferential Δx, we say p(x)=x and h(x) is the height of the region, in this case is h(x)= $4x-x^{2}-3$ . Then,