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Elenna [48]
3 years ago
15

A store owner wants to make a candy mix that sells for $1 per

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0

Step-by-step explanation:

the store owner should add 12.5 pounds of gummy candy

zloy xaker [14]3 years ago
3 0

The answer is 50 pounds

Hope this helps ^^

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2k-3(4-k)=3k+4 what is the value for x
Mumz [18]

Answer:

k=8

Step-by-step explanation:

2k-12+3k=3k+4

5k-12=3k+4

2x-12=4

2k=16

k=8

6 0
3 years ago
Which expression correctly represents “six more than the quotient of three and a number, decreased by eight”?
Hatshy [7]
6 + 3/x - 8

( six more = 6 +)
(The quotient of three and a number = 3/x)
(Decreases by eight = -8)
4 0
3 years ago
Read 2 more answers
Please give me the answer to this problem
Darya [45]

Total 27inch^

Calculation of 1 rectangle +1 triangle(11-7=4 is the base)

triangle    x^+4^=5^

                  x^+16=25

                  x^=9

                    x=3      (height=3)

Sides of triangle  Base=4   Hypotenuse=5     height =3 

area 1/2 4  x  3  =2x3=6

Area triangle =6

Area Rectanglel   7x3=21

21+6=27 inch^ total area



5 0
3 years ago
The mayor of a town has proposed a plan for the construction of a new community. A political study took a sample of 1300 voters
Kryger [21]

Answer:

The value of the test statistic is t = 2.19.

Step-by-step explanation:

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected mean, \sigma is the standard deviation and n is the size of the sample.

Sample of 1300 voters:

This means that n = 1300

Found that 45% of the residents favored construction.

This means that X = 0.45

A political strategist wants to test the claim that the percentage of residents who favor construction is more than 42%.

This means that \mu = 0.42, and by the Central Limit Theorem:

\frac{\sigma}{\sqrt{n}} = s = \sqrt{\frac{0.42*0.58}{1300}} = 0.0137

So, the test statistic is:

t = \frac{X - \mu}{s}

t = \frac{0.45 - 0.42}{0.0137}

t = 2.19

The value of the test statistic is t = 2.19.

3 0
3 years ago
Please help!
quester [9]

Answer:

The third one

Step-by-step explanation:

Median - Middle number in terms of value

Mode - outcome that appears the most

Mean - average ( add the numbers together and divide that by the amount of numbers )

Data without Kevins score

13, 21, 28, 9, 31

First let's find the mean

To find the mean we simply add the numbers up and divide that by the total amount of numbers ( there are 5 numbers )

13 + 21 + 28 + 9 + 31 = 102

102/5=20.4

So the mean without Kevins score is 20.4

Next let's find the mode

The mode is the number that appears the most

Looking at the data no number appears more than once so there is no mode

Finally let's find the median.

To make it easier to find let's list the numbers in order from least to greatest

9, 13 , 21 , 28, 31

We then go to the middle number ( which would be 21 )

The mode is 21

So for data without Kevins score the mean would be 20.4, the median would be 21 and the mode would be none

Now let's add in Kevin's score and repeat this process

Data with Kevin's score

13, 21, 28, 9, 31, 9

First let's find the mean

( Note that there is 6 numbers this time )

13 + 21 + 28 + 9 + 31 + 9 = 111

111/6 = 18.5

So mean with Kevin's score = 18.5

Next let's find the mode

The number 9 appears the most so the mode is 9

Finally let's find the mean

Once again let's list the numbers from least to greatest

9, 9, 13 , 21 , 28, 31

Because there is an even amount of numbers we will take the sum of the two middle numbers and divide that by 2

The two middle numbers would be 21 and 13

21 + 13 = 34

34/2=17

So median = 17

In the end we get the following

Without Kevins score

Mean = 20.4

Median = 21

Mode = none

With Kevin's score

Mean = 18.5

Median = 17

Mode = 9

This information corresponds with the third table

5 0
3 years ago
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