1. You have that:
- The homeowner<span> want the length of the swimming pool to be 4 feet longer than its width.</span>
- He wants to surround it with a concrete walkway 3 feet wide.
- He can only afford 300 square feet of concrete for the walkway.
2. Therefore, the tota area is:
At=L2xW2
L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
W2 is the width of the walkway (W1+3+3⇒W2=W1+6)
3. The area of the walkway is:
A2=At-A1
A2=300 ft²
4. Therefore, you have that the width of the swimming pool is:
A2=(W1+10)(W1+6)-(W1+4)(W1)
300=(W1²+6W1+10W1+60)-(W1²+4W1)
W1²+16W1+60-W1²-4W1-300=0
12W1-240=0
W1=240/12
W1=20 ft
5. And the length is:
L1=W1+4
L1=20+4
L1=24 ft
Answer:
The answer is 0/2
Step-by-step explanation:
The second y - the first y / the second x - the first x.
Step 1: 1 - 1 / 5 - 3
Step 2: 0 / 5 - 3
Step 3: 0 / 2
Answer:
y = -4.3
Step-by-step explanation:
40 = -10(y + 0.3) <em>{Step 1: Use the distributive property to multiply -10 by y + 0.3}</em>
40 = -10y + -10(0.3)
40 = -10y - 3 <em>{Step 2: Add 3 to both sides.}</em>
40 + 3 = -10y
43 = -10y <em>{Step 3: Divide both sides by -10}</em>
43/-10 = y
-4.3 = y
y equals -4.3.
