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kozerog [31]
3 years ago
9

A particular restaurant can legally have only 150 people in it at one time. The tables in the restaurant can seat 4 people at a

time. The number of tables, t, in the restaurant can be represented by the inequality 4t < 150. What is the maximum number of tables the restaurant can have?

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0
37.5 tables or round it up to 38

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A data set is a set of number is a data
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Answer:

Step-by-step explanation:

First, you need to find the GCF of both denominators.

That would be 21.

You would need to multiple the 7 in 4/7 by 3, to get to 21. That means you would also have to multiply 3 by the 4. You should get 12/21.

Do you same thing to 1/3.

After that you should get the 2 factions, 12/21 and 7/21

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An article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and
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Answer:

The 95% confidence interval for the proportion of all dies that pass the probe is (0.637, 0.733).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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356 dies were examined by an inspection probe and 244 of these passed the probe.

This means that n = 356, \pi = \frac{244}{356} = 0.685

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.685 - 1.96\sqrt{\frac{0.685*0.315}{356}} = 0.637

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.685 + 1.96\sqrt{\frac{0.685*0.315}{356}} = 0.733

The 95% confidence interval for the proportion of all dies that pass the probe is (0.637, 0.733).

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A=-3.8

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7 0
3 years ago
Read 2 more answers
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